Sqrt[2x^2-5x+1]=x-1

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Solution for Sqrt[2x^2-5x+1]=x-1 equation: 


Simplifying
Sqrt[2x2 + -5x + 1] = x + -1

Reorder the terms:
qrtS[1 + -5x + 2x2] = x + -1
[1 * qrtS + -5x * qrtS + 2x2 * qrtS] = x + -1
[1qrtS + -5qrtxS + 2qrtx2S] = x + -1

Reorder the terms:
1qrtS + -5qrtxS + 2qrtx2S = -1 + x

Solving
1qrtS + -5qrtxS + 2qrtx2S = -1 + x

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Reorder the terms:
1 + 1qrtS + -5qrtxS + 2qrtx2S + -1x = -1 + x + 1 + -1x

Reorder the terms:
1 + 1qrtS + -5qrtxS + 2qrtx2S + -1x = -1 + 1 + x + -1x

Combine like terms: -1 + 1 = 0
1 + 1qrtS + -5qrtxS + 2qrtx2S + -1x = 0 + x + -1x
1 + 1qrtS + -5qrtxS + 2qrtx2S + -1x = x + -1x

Combine like terms: x + -1x = 0
1 + 1qrtS + -5qrtxS + 2qrtx2S + -1x = 0

The solution to this equation could not be determined.

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